8 Bit Serial To Parallel Converter Verilog Code

Serial to parallel converter cable

2 bit serial to parallel conversion VHDL source code. This page of VHDL source code covers 2 bit serial to parallel conversion vhdl code and provides link to 2 bit parallel to serial conversion. In general a shift register is characterized by the following control and data. Adobe cc 2017 crack torrent. Synchronous/asynchronous parallel load; clock enable; serial or parallel output. 8-bit Shift-Left Register with Positive-Edge Clock, Serial In, and Serial Out. Following is the Verilog code for an 8-bit shift-left register with a negative-edge clock,.

Download gta v apk obb mobile. I want to convert 8 bit serial data into 8 bit parallel data my code is here library IEEE; use IEEE.STD_LOGIC_1164.all; entity PAR2SER is port( din: in STD_LOGIC; clk: in STD_LOGIC; reset: in STD_LOGIC; dout: out STD_LOGIC_VECTOR(7 downto 0) ); end PAR2SER; architecture sipo_behavior_arc of PAR2SER is begin sipo: process (clk,din,reset) is variable s: std_logic_vector(7 downto 0):= '00000000'; begin if (reset='1') then s:= '00000000'; elsif (rising_edge (clk)) then s:= (din & s(7 downto 1)); end if; dout. The waveform looks somewhat strange cause the simulation includes timing: the individual bits of dout switch with some delay with respect to the positive CLK-edge (~6ns.

If one takes this delay in consideration and looks at dout only at the 'next' rsising CLK-edge, then dout toggles between xAA and x55 - just as it should when din toggles with every CLK-cycle. One thing I do not understand is, that dout as std_logic_vector is displayed as 'uninitialized' every other CLK-cycle - though each individual bit of the std_logic_vector is showing a well defined logic value. Besides that the simu just shows, what one should expect from the given description. (By the way: Ser2Par would be a much more appropriate name for this component than Par2Ser). > but i am not getting correct data.

For me the wavrform looks fine: in the shift register is '01010101' or '10101010' at the rising edge of clk. What could you expect instead? BTW: do a behavioural simulation instead of this post route timing simulation. It makes things much easier and more obvious. > One thing I do not understand is, that dout as std_logic_vector is > displayed as 'uninitialized' every other CLK-cycle - though each > individual bit of the std_logic_vector is showing a well defined logic > value. That looks really kind of strange.